NPTEL Problem Solving Trough Programming In C | NPTEL Week 7 Programming Assignment | NPTEL Assignment Solutions

NPTEL Problem Solving Trough Programming In C Week 7 Programming Assignment | NPTEL Swayam Assignment Answers  

Nptel Week 7 Programming Assignment Answers:

Q.1: Write a C program to find the sum of all elements of each row of a matrix.

 Example:

For a matrix

 4 5 6

 6 7 3

 1 2 3

 The output will be

 15

 16

 6

Code:

int sum; for(i=0;i<r;i++){ sum=0; for(j=0;j<c;j++){ sum+=matrix[i][j]; } printf("%d\n",sum); } return 0; }

Q.2: Write a C program to find subtraction of two matrices i.e. matrix_A - matrix_B=matrix_C.

If the given martix are

 2 3 5 and 1 5 2 Then the output will be 1 -2 3

 4 5 6        2 3 4                                       2 2 2

 6 5 7        3 3 4                                       3 2 3

 The elements of the output matrix are separated by one blank space.

Code:

for(i=0;i<row;i++){ for(j=0;j<col;j++){ matrix_C[i][j]=matrix_A[i][j]-matrix_B[i][j]; printf("%d ", matrix_C[i][j]); } printf("\n"); } return 0; }

Q.3: Write a C program to print lower triangle of a square matrix.

For example the output of a given matrix

 2 3 4 will be 2 0 0

5 6 7      5 6 0

4 5 6      4 5 6

Code:

for(i=0;i<r;i++){ for(j=0;j<r;j++){ if(i<j){ matrix[i][j]=0; } printf("%d ", matrix[i][j]); } printf("\n"); } return 0; }

Q.4: Write a C program to print Largest and Smallest Word from a given sentence. If there are two or more words of same length, then the first one is considered. A single letter in the sentence is also consider as a word.

Code:

int i=0,j=0,k=0,strr,m=0,n=0,max=0,min=0; char c; while(str[k]!='\0') //for splitting sentence into words { j=0; while(str[k]!=' '&&str[k]!='\0' && str[k]!='.') { substr[i][j]=str[k]; k++; j++; } substr[i][j]='\0'; i++; if(str[k]!='\0') { k++; } } int len=i; max=strlen(substr[0]); min=strlen(substr[0]); //After splitting getting length of string and finding its index having max length and index having min length for(i=0;i<len;i++) { strr=strlen(substr[i]); if(strr>max) { max=strr; m=i; } if(strr<min) { min=strr; n=i; } } printf("Largest Word is: %s\nSmallest word is: %s\n",substr[m],substr[n]); return 0; }

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